Belt Conveyor Problem: Finding Length and Weight | Grain Density 700 kg/m^3

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    Belt Conveyor
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The discussion focuses on calculating the length and weight of a belt conveyor with a grain density of 700 kg/m^3, a belt velocity of 1.3 m/sec, and a height of 5m. The initial calculation for the length of the conveyor is deemed incorrect, with a suggestion that the tangent function is not applicable. Participants seek clarification on the term "conveing wight" and whether the height of the material on the conveyor is known. The conversation highlights the need for accurate definitions and calculations to solve the problem effectively. Overall, the thread emphasizes the importance of clear communication and correct mathematical application in engineering problems.
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hey ... i need help with this problem Grain density=700 kg/m^3
velocity of belt=1.3 m/sec
tan(theta)=tan(30)=0.6
hight=5m
wide of belt = 50cm

find:
1- real Length
2- conveing wight

look at pic

http://hh7.an3m1.com/Sep/an3m1.com_13608577291.png My answer : 1- sin(30)= 5\L
L= 10 * 2.5= 25m

2- conveing wight i need help with it
 
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Oh so many colors.
I don't understand how you tried to calculate the length, but the result is wrong. The tangens is not really useful here.

What is "conveing wight"? And do you have some height of the material on the conveyor?
 

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