Bending of Light in diffraction? Is it actually possible?

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The discussion centers on the bending of light in diffraction and whether such trajectories are genuinely possible. It highlights the wave-particle duality of light, explaining that light behaves as a probability function, with paths that can cancel each other out or continue in bent trajectories near edges. The bending is attributed to geometric optics and the wave nature of light, leading to apparent bending in diffraction patterns. The quantum perspective emphasizes that this "bending" is a result of the uncertainty principle, where knowing a photon's position at a slit leads to an unpredictable momentum. Overall, the phenomenon of light bending in diffraction is explained through both classical and quantum optics principles.
Aurghyadip Kundu
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I know light has wave particle duality, I understand these two points very well,
1. Light moves as a probability function, taking all the possible paths at once. The alternate paths cancel themselves out, resulting in a particle-like combined motion.

2. When relatively close to an edge, some paths will collide in the edge and their opposing pairs are thus not annihilated and continue at bent trajectories around the edge.

What I really want to know is, are those bent trajectories actually possible?
The gravitational pull of the Earth is not enough for the photons to take up a bent trajectory like a rock thrown. So, how can we explain this bent trajectory?
 
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A. Neumaier said:
This is explained through geometric optics, applied to the wave fronts of the diffracted wave.
See the corresponding wikipedia article:
Thank you for your reply.
I don't understand how we can explain that with the help of geometrical optics, I am asking for a bit elaborate answer. As light can not actually bend but, in diffraction phenomenon, light seems to be apparently bending.
I gave the article a read, could not find what I was looking for(That is, the diffraction phenomenon in quantum physics). It would be very helpful if you could quote that here.
 
Aurghyadip Kundu said:
Thank you for your reply.
I don't understand how we can explain that with the help of geometrical optics, I am asking for a bit elaborate answer. As light can not actually bend but, in diffraction phenomenon, light seems to be apparently bending.
I gave the article a read, could not find what I was looking for(That is, the diffraction phenomenon in quantum physics). It would be very helpful if you could quote that here.
I had quoted the piece that is relevant. Light has a wave nature, which bend, and light rays are perpendicular to all light fronts. In a diffraction experiment, this leads to bent rays at the fringes.
 
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Aurghyadip Kundu said:
As light can not actually bend but, in diffraction phenomenon, light seems to be apparently bending.

Here is the quantum answer to diffraction:
http://arxiv.org/ftp/quant-ph/papers/0703/0703126.pdf

As you can see no 'bending' involved. The apparent 'bending' is simply the uncertainty principle at work. At the slit you know its position so its momentum is unknown and after the slit can go off in all sorts of crazy directions.

Thanks
Bill
 
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bhobba said:
Here is the quantum answer to diffraction:
http://arxiv.org/ftp/quant-ph/papers/0703/0703126.pdf

As you can see no 'bending' involved. The apparent 'bending' is simply the uncertainty principle at work. At the slit you know its position so its momentum is unknown and after the slit can go off in all sorts of crazy directions.

Thanks
Bill
Thanks Bill.
Thanks a lot. I was precisely finding this.
 
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Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?

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