Water flows through a horizontal pipe and then out into the atmosphere at a speed v1 = 19 m/s. The diameters of the left and right sections of the pipe are 4.3 cm and 2.1 cm, respectively. (a) What volume of water flows into the atmosphere during a 16 min period? In the left section of the pipe, what are (b) the speed v2, and (c) the gauge pressure? 16 min = 960s D1 = Area = 3.46x10^-4 D2 = Area = 1.45x10^-3 So for part A. Rv = Av = (3.46x10^-4)(19)(960) = 6.32 m^3 For part B. A1v1 = A2v2 (3.46x10^-4)(19) = (1.45x10^-3)v2 V2 = 4.53m/s Im having problems with the gauge pressure: Pgauge = Po - Patm So for Po im using Burnoulli's Equation P1 - P2 = rho(g)(Y1-Y2) + 1/2 (rho)(V2^2 - V1^2) I assumed y to be constant and equal = 0 and density of water = 1000 so i had P1 -P2 = 1/2(1000)(19^2 - 4.53^2) so i got Pgauge = 1.6855 - Patm But i cant get it right. can somehow help me.