Water flows through a horizontal pipe and then out into the atmosphere at a speed v1 = 19 m/s. The diameters of the left and right sections of the pipe are 4.3 cm and 2.1 cm, respectively. (a) What volume of water flows into the atmosphere during a 16 min period? In the left section of the pipe, what are (b) the speed v2, and (c) the gauge pressure?(adsbygoogle = window.adsbygoogle || []).push({});

16 min = 960s

D1 = Area = 3.46x10^-4

D2 = Area = 1.45x10^-3

So for part A.

Rv = Av = (3.46x10^-4)(19)(960) = 6.32 m^3

For part B.

A1v1 = A2v2

(3.46x10^-4)(19) = (1.45x10^-3)v2

V2 = 4.53m/s

Im having problems with the gauge pressure:

Pgauge = Po - Patm

So for Po im using Burnoulli's Equation

P1 - P2 = rho(g)(Y1-Y2) + 1/2 (rho)(V2^2 - V1^2)

I assumed y to be constant and equal = 0 and density of water = 1000

so i had P1 -P2 = 1/2(1000)(19^2 - 4.53^2)

so i got Pgauge = 1.6855 - Patm

But i cant get it right. can somehow help me.

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Bernoulli's Equation on water flow

**Physics Forums | Science Articles, Homework Help, Discussion**