- #1
naman007
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for a stream line flow of ideal liquid (non-viscous) imcompressible the sum of pressure energy per unit volume kinetic energy per unit volume , potential energy per unit volume remains constant
mathematically
P+1/2roV2+ROGH=constant
consider a fluid flowing in a pipe of various crossections
we consider 2 regions ,
at region 1 the workdone =P1V
workdone at region 2 =P2V
total workdone =P2V-P1V
= V(P1-P2)
Change in gravitational potential energy
U=ro×g×V(H2-H1)
the change in kinetic energy
= 1/2×ro×V(V2-V1)
where v1 and v2 are the speed of liquid
aplling work energy theorem
(P1-P2)V=ro×g(H2-H1) + 1/2ro(V2-V1)
P1+ro×gh1+1/2rov1=P2+ro×gh2+1/2rov2
that is P+ro×gh+1/2ro×v= constant
mathematically
P+1/2roV2+ROGH=constant
consider a fluid flowing in a pipe of various crossections
we consider 2 regions ,
at region 1 the workdone =P1V
workdone at region 2 =P2V
total workdone =P2V-P1V
= V(P1-P2)
Change in gravitational potential energy
U=ro×g×V(H2-H1)
the change in kinetic energy
= 1/2×ro×V(V2-V1)
where v1 and v2 are the speed of liquid
aplling work energy theorem
(P1-P2)V=ro×g(H2-H1) + 1/2ro(V2-V1)
P1+ro×gh1+1/2rov1=P2+ro×gh2+1/2rov2
that is P+ro×gh+1/2ro×v= constant