Bijection of Cartesian products

The1TL
Messages
23
Reaction score
0
How can I prove this:
Let A, B, and C be non empty sets. If A is bijective to B, then A x C is bijective to B x C.



also if A and B are bijective Power set of A is bijective to Power set of B



and finally Fun(A,C) is bijective to Fun(B,C)
 
Physics news on Phys.org
any help?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top