Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Binding Energy

  1. Feb 25, 2014 #1
    The graph of potential energy of two nucleons shows a minima at 100 MeV,but the binding energy of a deuterium nucleus is close to just 1 MeV.

    Since binding energy is the energy required to rip apart the nucleus ,hypothetically,should the two values not be same?
     
  2. jcsd
  3. Feb 25, 2014 #2

    ChrisVer

    User Avatar
    Gold Member

    Can you show the graph?
    In general the binding energy of two nucleons depends on the nucleon type (eg nn and pp are not possible).... For having a bound state you need E<0.
     
  4. Feb 25, 2014 #3
    Please see the attachment.
     

    Attached Files:

  5. Feb 25, 2014 #4

    ChrisVer

    User Avatar
    Gold Member

    I guess that this graph wants to describe the fact that the nucleons will prefer existing within the nuclei radius, rather than going too far away or falling on each other
     
  6. Feb 25, 2014 #5
    No, they don't have to be the same. Look at the hydrogen atom, for instance. The electron's binding energy is 13.6 eV while the minimum energy of the coulomb potential is -∞.
     
  7. Feb 25, 2014 #6

    mfb

    User Avatar
    2015 Award

    Staff: Mentor

    The minimum potential is just a lower bound for the binding energy - and you would need particles of "infinite" mass to approach this value. The real nucleons will form some (3-dimensional) wave-function similar to the electron, and have an energy corresponding to a solution of the Schrödinger equation (ignoring relativistic effects).
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted