Binomial Distribution Practice: Part A Solution & Part B Explanation

AI Thread Summary
The discussion focuses on solving a homework problem involving binomial distributions for two types of eggs. For Part A, the user successfully calculated probabilities for Egg A and Egg B using the binomial formula and multiplied the results. In Part B, confusion arises regarding the cases of broken eggs, with attempts to calculate probabilities for combinations of broken eggs (AA, BB, AB). Despite trying to multiply and add the probabilities, the user did not arrive at the correct answer and sought assistance. Ultimately, another participant provided a solution that clarified the approach.
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Homework Statement



http://puu.sh/dOcM
Answer:
http://puu.sh/dOcZ

Homework Equations



The Attempt at a Solution


I got Part A.
For part A, this is what I did:

I did Egg A: X ~ (6,(1/6)) P(X = 1) and did something similar for Egg B. I then multiplied both to get the answer for Part A.
http://puu.sh/dOfV

For Part B, I'm a bit confused. I tried doing cases. As in:
(broken eggs): AA , BB , AB (same as BA)
Then I did:
AA: X ~ (6,(1/6)) P(X = 2)
BB: Y ~ (6,(1/10)) P(X = 2)
AB: X ~ (6,(1/6)) P(X = 2) * Y ~ (6,(1/10)) P(X = 2)

My work:
http://puu.sh/dOh8


And then, I tried multiplying and adding the three values. But I didn't get the correct answer.

Could someone help me out please? Thanks
 
Last edited by a moderator:
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If two type A are broken then we must have 0 type B broken in order to have two broken altogether.

RGV
 
Wow, thanks. I tried it out. It works :) thanks.
 

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