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Binomial distribution

  1. Jun 5, 2014 #1
    please refer to the second line of solution, since we only concerned about the probability of getting number (5) , then why cant I just just say P=(5/6)^5 , why should I times =(5/6)^5 with (1/6)^2 ?
     

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  3. Jun 5, 2014 #2

    Erland

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    (5/6)^5*(1/6)^2 is the probability to get five non-fives followed by two fives, when throwing the die seven times. (5/6)^5 is just the probabability to get non-fives the five first times, regardless of if you get any more fives the two last times.
     
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