(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

In the real world trimolecular reactions are rare, although trimerizations are not. Consider

the following trimerization reaction in which three monomers of A combine to form the

trimer C,

A + A [itex]\Updownarrow[/itex] B, where k_{1}and k_{-1}are the forward and reverse rate constants respectively.

and,

A + B [itex]\Updownarrow[/itex] C. where k_{2}and k_{-2}are the forward and reverse rate constants respectively.

(a) Use the law of mass action to ﬁnd the rate of production of the trimer C.

(b) Suppose k_{−1}>> k_{−2}, k_{2}A. Use the appropriate quasi-steady-state approximation to ﬁnd the rates of production of A and C, and show that the rate of production of C is proportional to [A]^{3}. Explain in words why this is so.

2. Relevant equations

law of mass action, quasi-steady-state approximation

3. The attempt at a solution

let c = concentration of C, a = concentration of A, b = concentration of B

using law of mass action:

dc/dt = k_{2}ab - k_{-2}c

Is this correct??

Also I don't know how to go about part b? don't really understand the quasi-steady state for this system.

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# Homework Help: Biological mathematics - trimerisations - law of mass action

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