BJT single stage amplifier we write gm=Ic/VT

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    Amplifier Bjt
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Discussion Overview

The discussion revolves around the small-signal model of a BJT single stage amplifier and the implications of using a Darlington pair configuration. Participants explore the calculation of transconductance (gm) and the thermal voltage (VT) in this context, including the effects of multiple transistors on these parameters.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant states that for a BJT single stage amplifier, gm is defined as Ic/VT, where VT is approximately 26 mV.
  • Another participant clarifies that each device in a Darlington pair has its own gm calculated as Ic divided by its respective VT, which is around 25.7 mV for each device.
  • A participant questions whether the overall gm for the Darlington pair should be calculated using a combined VT of 52 mV, suggesting that the cumulative effect of two forward active PN junctions should be considered.
  • One response indicates that to find the voltage gain of the Darlington pair, it is appropriate to use 2*VT in the calculations.
  • Another participant expresses the need to solve a specific problem related to the Darlington pair and mentions the intention to multiply gm by the output resistance.
  • A repeated inquiry about the inclusion of the Boltzmann constant in the calculation of VT highlights a desire for clarification on this concept.

Areas of Agreement / Disagreement

Participants express differing views on how to calculate the overall gm for a Darlington pair, particularly regarding the value of VT to be used. There is no consensus on whether to use a combined VT of 52 mV or to treat each transistor separately with its own VT.

Contextual Notes

Some assumptions about the operation of BJTs and the specifics of the Darlington configuration may not be fully articulated, and the discussion includes unresolved mathematical steps related to the calculation of gm and voltage gain.

pforpashya
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For BJT single stage amplifier we write gm=Ic/VT where VT is Thermal voltage whose value is 26mv. Now if we have a Darlington pair i.e. two transistor connected in CC-CC mode what will be overall gm.

Will the collector current Ic be divided by 52mv or 26mv. (Because in gain equation gm comes)

as their are two forward active PN junctions ...the cumulative change in VT is 52mV?

is this correct?

can someone through light on "why we have to include Boltzmann constant in calculation of VT"
in simple words?

Thanks in advance
 
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Each device has gm value equal to its own Ic divided by VT, where VT is 25.7 mV for each device. For a Darlington, if the input device is no. 1, and output device is no. 2, then Ie1 = Ib2, Ic1 = α1*Ie1, Ic2 = β2*Ib2, or Ic2 = α2*Ie2, .

This should get you started.

Claude
 
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ok. thank you for your reply. to find overall gm (i.e. gm2 as gm1 of first pair in darlington is very small) of the device should i divide Ic2 by VT1+VT2 i.e. 52mV?
 
Yes you should use 2*Vt if you want to find voltage gain.

The small signal gain for CE amplifier is equal to

\Large \frac{Vout}{Vin} =-\frac{Rc (\beta 1+\beta 2+\beta 1 \beta 2)}{(1+\beta 1) (re1+re2+re2 \beta 2)}

Where

re1 ≈ 1/gm1
re2 ≈ 1/gm2
 
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Thanks a lot...I have to solve one unsolved problem on darlington pair before saturday. I hope i will get right answer as i have to just multiply gm by output resistance of darlington pair.
 
can someone through light on "why we have to include Boltzmann constant in calculation of VT"
in simple words?
 

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