Black hole falling time for external observer

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SUMMARY

The discussion centers on the time experienced by an external observer at infinity when an object falls into a Schwarzschild black hole. It is established that an object cannot start from rest at the Schwarzschild surface due to its nature as a null surface. Instead, any inward trajectory will have a nonzero velocity upon crossing this surface. Furthermore, the time experienced by an external observer diverges to infinity as the object approaches the Schwarzschild surface, indicating that the internal time to fall from the horizon to the singularity cannot be directly correlated with external time.

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  • Understanding of Schwarzschild black holes
  • Familiarity with null and timelike geodesics
  • Knowledge of general relativity concepts
  • Basic grasp of coordinate systems in spacetime
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  • Study the properties of Schwarzschild solutions in general relativity
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  • Explore the concept of time dilation in strong gravitational fields
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Physicists, astrophysicists, and students of general relativity who are interested in the dynamics of black holes and the nature of time in extreme gravitational fields.

keithdow
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It is well know that it takes pi*m time to go from rest at the surface of a Schwarzschild black to the singularity. How much time does an external observer at infinity experience then in that time? How do I show it?
 
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Hm, well in the first place you cannot "start from rest" from the Schwarzschild surface, since it is a null surface. Only an outward going null geodesic can be at rest there, and any timelike curve will cross it with a nonzero inward velocity.

The external time has already gone to plus infinity when you reach the Schwarzschild surface. The inside is a different coordinate patch, in which the radial coordinate r has become the timelike coordinate. So whatever "time" it takes to fall from the horizon to the singularity, there is no way to correspond it to external time.
 

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