# Block Diagram of Transfer function

1. Jun 18, 2010

### jahlin

1. The problem statement, all variables and given/known data

Simplify the block diagram in figure and obtain the closed-loop transfer function. The first attachment is the question and the second attachment is the first step to the simplification of the block diagram.

2. Relevant equations

What i dont understand is how do you get rid off the summing point before the last block and replace it with the block( (1/G2(s))+1) in the first step. I dont understand the first step at all. any help would be appreciated. thanks.

3. The attempt at a solution

#### Attached Files:

• ###### step1.JPG
File size:
9.8 KB
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129
2. Jun 19, 2010

### Filip Larsen

You mention two attachments, but I only see one. I am guessing that you "only" have trouble identifying which simple reductions that have been employed from first to second diagram, but without seeing both diagrams its probably hard for people here to give you help.

3. Jun 19, 2010

### jahlin

heres the block diagram which i refer to in my original post.

the above attachment is the 1st step in reducing this block diagram.

#### Attached Files:

• ###### control.JPG
File size:
9.1 KB
Views:
114
4. Jun 19, 2010

### Filip Larsen

Note, that the last sum node is not involved in any feed-back loops, so its input is simply two parallel blocks with a common input, which can be reduced to a single block with a sum. Picking the first hit I get when searching for "control block reduction" [1] as reference, the reduction can be seen as a case of applying rule 4. You should be able to find the reduction in your textbook if it has a similar list of rules.

[1] http://www.msubbu.in/sp/ctrl/BD-Rules.htm

5. Jun 19, 2010

### jahlin

what i fail to figure out is (1/G2) + 1 where this +1 comes from.