When resolving all of the VERTICAL forces in a block that is being pushed up an incline with some incline amount theta, then when PUSHING with force P at an angle of alpha on the block, then the vertical component of force P is sin (alpha) * P in the downward direction (opposite of the Normal force); however, when pulling the block UP the incline with same alpha and same force P, then the vertical force is sin (alpha) * P upwards in the SAME direction as the normal force N. In both cases friction is in the direction of DOWN the incline. In both cases the Parallel and Perpendicular forces of gravity are the same. So, it would seem that the force P needed to push the block will be different than the force necessary to pull the block. Then seems counter-intuitive. Am I thinking correctly here?