Block on Wall Static Friction (Springs)

Click For Summary
SUMMARY

The discussion focuses on calculating the coefficient of static friction between a 1.64-kg block and a vertical wall using a spring with a spring constant of 500 N/m. The block is held in place by a spring compressed by 0.0400 m, generating a force of 20 N. The correct approach involves equating the force of friction to the normal force multiplied by the coefficient of friction, leading to the conclusion that the coefficient of static friction is 0.8, not 1.24 as initially calculated.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with Hooke's Law (F = kx)
  • Knowledge of static friction and its calculation (Ff = µFn)
  • Basic algebra for solving equations
NEXT STEPS
  • Study the principles of static and kinetic friction in detail
  • Learn about Hooke's Law and its applications in mechanics
  • Explore the concept of normal force in various contexts
  • Practice solving problems involving forces on inclined planes and vertical surfaces
USEFUL FOR

Students in physics, particularly those studying mechanics, as well as educators looking for examples of static friction applications in real-world scenarios.

Hypnos_16
Messages
148
Reaction score
1

Homework Statement


To measure the static friction coefficient between a 1.64-kg block and a vertical wall, the setup shown in the drawing below is used. (The dots are only there because spaces didn't work)
......|
......|W
SPRING----->(Block)|A
......|L
......|L
......|
A spring (spring constant = 500 N/m) is attached to the block. Someone pushes on the end of the spring in a direction perpendicular to the wall until the block does not slip downward. The spring is compressed by 0.0400 m. What is the coefficient of static friction?

K = 500n/m
m = 1.64kg
x = 0.0400m

Homework Equations



I know that the force by the spring pressing against the block is 20N since i used F =kx
I also know that the force of gravity is 16.1N

The Attempt at a Solution



I've attempted finding force by the spring on the block = 20N
Force of gravity = 16.1N
then subbing the two in.
Ff = µFn
20 = µ(16.1)
µ = 1.24

But that's not the right answer.
Doesn't it only matter with the forces in the direction of motion?
so since the block would be falling, how does the spring come into play?
I'm kind of confused
 
Physics news on Phys.org
Hi Hypnos_16! :smile:
Hypnos_16 said:
Ff = µFn
20 = µ(16.1)

erm :redface: … your numbers don't fit your letters :wink:
 
How do you mean?
The force of gravity is the only thing working in the y direction so Fn = Mg
And i figured the force of friction would be the force required to keep it from moving.
 
16.1 = µ(20) :wink:
 
You're joking me! wow. I feel like an idiot now...and yep, that's the right answer. Thanks man!
 

Similar threads

Replies
61
Views
3K
  • · Replies 18 ·
Replies
18
Views
1K
  • · Replies 6 ·
Replies
6
Views
1K
Replies
2
Views
2K
Replies
2
Views
2K
  • · Replies 33 ·
2
Replies
33
Views
2K
Replies
24
Views
4K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
8
Views
6K
  • · Replies 16 ·
Replies
16
Views
3K