Bode Phase plot of a second order system

Click For Summary
To draw a Phase Bode plot for a second-order system, understanding the damping ratio (ζ) is crucial, as it influences the phase transition between 0° at low frequencies and 180° at high frequencies. The damping ratio determines the system's response characteristics: over-damped (ζ > 1) results in slow response, under-damped (ζ < 1) leads to overshoot, critically damped (ζ = 1) is the fastest without oscillations, and ζ = 0 indicates oscillation. Each pole or zero in the system contributes to phase changes, and accurate phase plotting may require software for complex poles. The asymptotic approach is effective for real poles and zeros, but complex poles necessitate a more precise frequency response analysis. Understanding these relationships will aid in accurately constructing the Phase Bode plot for second-order systems.
bumclouds
Messages
24
Reaction score
0
Hey guys.

I need to know how to draw a Phase Bode plot of a Second order system.

I understand and can draw the Gain(Magnitude) Bode plot, but I can't seem to get the grip of the Phase one.

As far as I know there is an asymptote at 0^{o} at low frequencies and an asymptote at 180^{o} at high frequencies. But the transition between the two changes with damping factor.

Do any of you know the relationship between damping factor and the asymptotes so that I am able to draw an accurate Phase Plot of 2nd Order Systems?

Thanks guys
 
Engineering news on Phys.org
Dunno about "damping factor". A second order system might have two poles, or a pole and a zero. Each pole or zero will introduce a phase change in the frequency region near it:

http://en.wikipedia.org/wiki/Bode_plot
 
bumclouds said:
Do any of you know the relationship between damping factor and the asymptotes so that I am able to draw an accurate Phase Plot of 2nd Order Systems?

Let's say you've got a transfer function

\frac{X(s)}{U(s)}=\frac{G\cdot\omega^2}{s^2+2\zeta\omega s+\omega^2}

Then \zeta is your damping ratio. If I remember correctly, the damping ratio determines the shape of the step response and impulse response of the system.

If \zeta &gt; 1 then the system is over-damped and the system response is slow.
If \zeta &lt; 1 then the system is under-damped and the output has overshoot or ringing before reaching steady-state.
If \zeta = 1 then it is critically damped, which is the fastest response without oscillations.
If \zeta = 0 then it oscillates.

The location of the poles on the s-plane can be determined from damping ratio (or the damping ratio can be calculated if you know the location of the poles).

Set the denominator in the above equation to zero and solve for s to get the locations of the poles.

(sorry, running out of time, hope this helps you get started...)
 
berkeman said:
Dunno about "damping factor".

that "zeta" coefficient that is related to Q. i think that's what it is.

A second order system might have two poles, or a pole and a zero.

i wouldn't call a system with one pole and one zero a "second-order system". it's a first-order system.

Each pole or zero will introduce a phase change in the frequency region near it:

http://en.wikipedia.org/wiki/Bode_plot


i thought that Bode plots (using these asymptotes) were good when the poles and zeros were real (so the system can be modeled as a cascaded sections of smaller first-order systems). if the poles/zeros are complex and not so awful close to the real axis, then you need to plot out the frequency response legitimately (using a plotting function in software) instead of the asymptotic approximation approach using Bode plots. you can determine where the asymptotes go, but the behavior around the corners (where asymptotes meet) will be a lot different for complex pole pairs compared to real poles.
 
Thread 'I thought it was only Amazon that sold unsafe junk'
I grabbed an under cabinet LED light today at a big box store. Nothing special. 18 inches in length and made to plug several lights together. Here is a pic of the power cord: The drawing on the box led me to believe that it would accept a standard IEC cord which surprised me. But it's a variation of it. I didn't try it, but I would assume you could plug a standard IEC cord into this and have a double male cord AKA suicide cord. And to boot, it's likely going to reverse the hot and...

Similar threads

Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
5K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 4 ·
Replies
4
Views
5K
  • · Replies 4 ·
Replies
4
Views
9K
Replies
11
Views
7K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
2
Views
1K