Bode Plot Application: Increase Frequency Response & Magnitude Understanding

AI Thread Summary
Understanding Bode plots is essential for analyzing frequency response and magnitude in control systems. The discussion emphasizes that each Bode plot consists of two diagrams: one for magnitude and another for phase, which must be correlated as they represent the same circuit. To learn how to create Bode plots, one should start with the transfer function, such as H(jω) = Vout/Vin, and calculate the magnitude and phase functions, requiring basic mathematical knowledge. The conversation highlights the importance of grasping the concepts of poles and zeros in the context of the Laplace transform. Mastery of these elements is crucial for effectively utilizing Bode plots in engineering applications.
SDRFG
Messages
26
Reaction score
1
Hello,
After long time i am able to find Laplace transform function but can't understand the bode plot which give information of frequency response and magnitude i think
plaese anyway here how can push my thinking ahead in it?
 
Engineering news on Phys.org
https://en.m.wikipedia.org/wiki/Bode_plot

You can't get a whole semester course from an online forum. I suggest that you try hard to understand the wiki article linked. After that, you can return here with more specific questions and we will try to help.
 
  • Like
Likes SDRFG
ok, there is function s+1/s+2

how to draw bode plot?
You can't get a whole semester course
i was not able to understand at that time.
Bode_High-Pass.PNG
 
Should both diagrams be correlated?
 
  • Like
Likes SDRFG
no because one show for phase and another show for magnitude.
 
SDRFG said:
no because one show for phase and another show for magnitude.
Sorry - but this is not an answer to my question (I did not ask if both are "equal").
The complete BODE diagram for each frequency dependent network consists of TWO drawings: (a) Magnitude vs. frequency and (b) phase vs. frequency.
You have shown two such diagrams - however, it seems that they are not for the same circuit (because the must be correlated!).
 
  • Like
Likes SDRFG
i have no idea get it from wiki.
any way how they should be correlated..
 
As I wrote already: Each frequency-dependent circuit (most simple example: RC lowpass) can be split into a magnitude and a phase function.
That is pure mathematics: H(jω)=|H(ω)|*exp(φ(ω)).
So you have two functions which are, of course, correlated because they come from the same circuit.
 
  • Like
Likes SDRFG
how to learn bode plot??
 
  • #10
SDRFG said:
how to learn bode plot??
Simple answer: Learn how to produce a graphical representation of magnitude and phase of a simple frequency-dependent network (R-C combination).
Start with H(jw)=Vout/Vin and calculate magnitude and phase functions. This requires some basic math knowledge.
 
  • Like
Likes SDRFG
  • #11
Start with H(jw)=Vout/Vin and calculate magnitude and phase functions. This requires some basic math knowledge.
i have got Vo/Vi=s+1/s+2
 
  • #12
SDRFG said:
i have got Vo/Vi=s+1/s+2
I suppose you mean (s+1)/(s+2), correct?
* Do you know the meaning of "s"?
* Are you able to write down the expressions for magnitude and phase?
 
  • #13
after that i dnt not no please teach me after what is s and s=jw may be zero poles
no i frget i will remijnd if you follow
 

Similar threads

Replies
6
Views
4K
Replies
3
Views
2K
Replies
4
Views
20K
Replies
3
Views
2K
Replies
9
Views
4K
Replies
4
Views
2K
Replies
4
Views
8K
Back
Top