Bomb explosion -- calculating the momentum of one of the fragments

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SUMMARY

The discussion centers on calculating the momentum of fragments resulting from a bomb explosion. Participants agree that the total momentum of the two moving fragments must be balanced by the momentum of a third fragment, regardless of their individual directions. The calculation presented, ##p\sqrt5##, is acknowledged but questioned as potentially incorrect. Ultimately, the consensus is that the direction of movement does not affect the requirement for momentum conservation.

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rudransh verma
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Homework Statement
A bomb at rest explodes into 3 parts of the same mass. The momentum of the 2parts is -2pi^ and pj^. The momentum magnitude of the third part will be
Relevant Equations
##\vec R=\sqrt{{a\hat i}^2+{b\hat j}^2}##
I think if the two parts move in -x and +y direction, it must be balanced by the resultant of the two vectors but in opposite direction.
So ##p\sqrt5## will be the answer.
But I don’t think this is the right way to solve this.
 
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rudransh verma said:
I think if the two parts move in -x and +y direction, it must be balanced by the resultant of the two vectors but in opposite direction.
It doesn't matter what direction the two parts move. Their total momentum must be balanced by that of the third part.
rudransh verma said:
But I don’t think this is the right way to solve this.
Why not?
 
Doc Al said:
It doesn't matter what direction the two parts move. Their total momentum must be balanced by that of the third part.
Oh. So this is right. Thanks again.
Can you verify my other post?
 
rudransh verma said:
Can you verify my other post?
What post? Provide a link.
 

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