Bonding in Solid State Physics

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SUMMARY

The discussion focuses on the potential energy equation between two ions in solid state physics, defined as u(r) = -α/r² + β/r⁸. The equilibrium intermolecular distance, ro, is derived as ro = (4β/α)^(1/6) by setting the derivative du/dr to zero. Additionally, the inter-atomic distance R for which the potential energy is zero is expressed as R = (4)^(-1/6)ro. A clarification is provided regarding the presence of the constant 4 instead of 2 in the final expression for R.

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  • Understanding of potential energy equations in solid state physics
  • Knowledge of calculus, specifically differentiation
  • Familiarity with intermolecular forces and distances
  • Basic concepts of ionic bonding and energy minimization
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  • Explore the role of constants in potential energy equations
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Students and researchers in solid state physics, particularly those focusing on ionic bonding and potential energy calculations in materials science.

RedMech
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1. The problem statement

The potential energy between two ions is
u(r) = -α/r2 + β/r8

Determine:

(i) The intermolecular distance ro for which the potential energy is minimum
(ii) The inter-atomic distance for which the potential energy is zero is

R= (2)-1/6ro

Homework Equations



du/dr=o at equilibrium distance, ro

The Attempt at a Solution



i) du/dr= 2α/r3 - 8β/r9 = 0 at equilibrium distance ro

we end up with

ro = (4β/α)1/6



ii) -α/r2 + β/r8 = 0

which give us

R-6 = α/β

We can express the ratio α/β interms of ro so that

R-6 = 4ro-6

and finally

R = (4)-1/6ro

My question now is why does my answer have a 4 instead of a 2 in it?
 
Last edited:
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Your result is correct, and it can be written also as R=2-1/3 r0.

ehild
 

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