Boolean function - minterms - literals

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The discussion focuses on converting a Boolean function F(A, B, C, D, E) into a sum of products form with minimal literals and expressing it as a sum of minterms. A truth table has been created, resulting in 11 terms for the function. The participant is uncertain whether to use a Karnaugh map for simplification or to apply Boolean algebra. Additionally, there is confusion regarding the concepts of complement and dual in Boolean algebra. The thread concludes with the participant seeking clarification on these concepts while noting that their initial problems have been resolved.
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Boolean function - minterms -- literals

Homework Statement


(a) Describe the circuit in a form of a Boolean function F(A, B, C, D, E). Convert this
expression to the sum of products form that includes minimal number of literals, and next
express this function as a sum of minterms, namely F(A, B, C, D, E) = m(….).

Homework Equations



xx

The Attempt at a Solution



I wrote out a truth table for the function and have a total of 11 terms. I might as well write it out here:

F = A'B'CD'E + A'B'CDE + A'BC'DE + A'BCD'E + A'BCDE + AB'C'DE + AB'CD'E + AB'CDE + ABC'DE + ABCD'E + ABCDE

next step: Convert this expression to the sum of products form that includes minimal number of literals.

Do they want me to K-map the function, or do they want me to simplify the expression algebraically (boolean algebra obviously)?EDIT: one more question: What is the difference between a complement and a dual??
 
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I have another question, and I didn't want to make another thread. My question is attached into this post.

Commutative

xy = yx

Associative

x + y = y + x


so, are they asking me to prove:

(x -> y) = ( y -> x)

and

(x -> y) + (y -> x) = (y -> x) + (x -> y)


This question is really confusing me.

Thanks for help in advance.
 

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Both problems solved.

Still don't understand what the difference between a compliment and a dual is though.
 
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