Boundary conditions for fluid flow

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SUMMARY

The discussion centers on the boundary conditions for nonviscous, incompressible fluid flow, specifically examining the velocity of fluid at the surface of a sphere with uniform incident velocity. It is established that the radial velocity at the surface does not vanish, contrary to expectations based on magnetostatics principles. The no-slip boundary condition is referenced, and the mathematical expressions for the velocity components are derived from Frank M. White's "Fluid Mechanics." The radial component of velocity is shown to vanish at the surface when evaluated correctly.

PREREQUISITES
  • Understanding of nonviscous, incompressible fluid dynamics
  • Familiarity with boundary conditions in fluid mechanics
  • Knowledge of mathematical modeling in fluid flow, particularly using potential functions
  • Basic principles of magnetostatics for comparative analysis
NEXT STEPS
  • Study the no-slip boundary condition in fluid mechanics
  • Explore potential flow theory and its applications
  • Learn about boundary layer theory and its implications on fluid flow
  • Investigate the mathematical derivation of velocity components in fluid dynamics
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Fluid mechanics students, researchers in fluid dynamics, and engineers working on applications involving nonviscous fluid flow will benefit from this discussion.

Euclid
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What are the general boundary conditions for nonviscous, incompressible fluid flow? I am trying to find the velocity of fluid at the surface of a sphere with the incident fluid having uniform velocity. I am surprised to find in the solution that the radial velocity at the surface does not vanish. For magnetostatics, div B = 0 implies B-perp is continuous. Would not div v= 0 imply the same for v-perp?
What about the same problem but incident upon an infinite plane? Would the velocity not vanish at the surface?
 
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I gather you are asking about the no-slip boundary condition?
 
From Fluid Mechanics by Frank M. White

[tex]\psi = -\frac{1}{2} U r^2 sin^2 \theta + \frac{\lambda}{r} sin^2\theta[/tex]

[tex]\psi = 0 => r = a = (\frac{2\lambda}{U})^{1/3}[/tex]

[tex]v_r = -\frac{1}{r^2 sin\theta} \frac{\partial \psi}{\partial \theta}[/tex]

[tex]v_r = U cos\theta (1 - \frac{a^3}{r^3})[/tex]

so the radial component does appear to vanish at the surface [tex]r = a[/tex]
 

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