Break down CaCO3 into its constituents

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To calculate the daily throughput of a reverse osmosis plant supplying 4.5 million liters of drinking water with a minimum hardness of 60 mg l-1 as Ca, it is essential to break down CaCO3 into its constituents. The feed hardness is given as 660 mg l-1 CaCO3, while the permeate hardness is only 4 mg l-1. The problem indicates that 30% of the feed will be rejected, which must be factored into the throughput calculation. The user seeks guidance on how to approach this problem, indicating a need for foundational understanding in the sciences. This discussion highlights the importance of clarity in tackling complex scientific calculations.
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Homework Statement



in order for a well to supply 4.5 million litres of drinking water per day, at a minimum total hardness of 60mg l-1 as Ca, calculate the daily throughput of the reverse osmosis plant assuming that 30% of the feed to the plant comes out as reject.

Homework Equations



a table provides the following info:
total hardness (as mgl-1 CaCO3) at feed is 660 but at permeate it is 4

The Attempt at a Solution



i suspect i must break down CaCO3 into its constituents however i can't remember how to do this. Iwould be very grateful for a pointer in the right direction.
 
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guys I am only a newbie to both the sciences and this great website, I am not looking for an exact answer but just a clue of how to tackle this question. if any further questions is needed please reply, i really am going off my head trying to get over this mental block I am having.
 
Perhaps you should post this under the "Other Sciences" sub-forum, also under Homework & Coursework Questions
 

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Calculating CaCO3 Breakdown for 4.5M Litres of Water/Day
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