Buckling length of column

AI Thread Summary
The discussion focuses on deriving the buckling length of a column using specified boundary conditions. The boundary conditions include displacement and slope constraints at both ends of the column, as well as a moment condition at the origin. Participants are seeking assistance in expressing the governing equations in terms of the parameter ωL. The equations involve constants c1 and c2, which are derived from the boundary conditions and relate to the column's deflection and moment. The conversation highlights the complexities of applying these conditions to achieve a solution for the buckling length.
rc2008
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Homework Statement
I was given this question to find the buckling length of the non-sway frame of column AB.
Relevant Equations
The general equation is v" +## \omega\##^2 v = MB/EI + Vx/EI,
Taking B as origin, the boundary condition provided was ##v(x=0)= 0 , v(x=L)=0 , v'(x=0)= \theta B##
##v'(x=L)=0## , and also ##v'' (x=0) = M_B/ EI##

However, I had problem of expressing the equation in terms of ## \omega L##
Can anyone help ?

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## BC1: At x=0x = 0x=0, v=0v = 0v=0: c2+θBL=0c_2 + \frac{\theta_B}{L} = 0c2+LθB=0• BC2: At x=Lx = Lx=L, v=0v = 0v=0: c1sin⁡(ωL)+c2cos⁡(ωL)+VEIL+θBL=0c_1 \sin(\omega L) + c_2 \cos(\omega L) + \frac{V}{EI} L + \frac{\theta_B}{L} = 0c1sin(ωL)+c2cos(ωL)+EIVL+LθB=0• BC3: At x=0x = 0x=0, v′=θBv' = \theta_Bv′=θB: c1ω+VEI=θBc_1 \omega + \frac{V}{EI} = \theta_Bc1ω+EIV=θB• BC4: At x=Lx = Lx=L, v′=0v' = 0v′=0: c1ωcos⁡(ωL)−c2ωsin⁡(ωL)+VEI=0c_1 \omega \cos(\omega L) - c_2 \omega \sin(\omega L) + \frac{V}{EI} = 0c1ωcos(ωL)−c2ωsin(ωL)+EIV=0• BC5: At x=0x = 0x=0, Moment MB=EIv′′M_B = EI v''MB=EIv′′: −c2ω2=2EILθB-c_2 \omega^2 = \frac{2EI}{L} \theta_B−c2ω2=L2EθB##
 
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