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What is the minimum length of the column at which buckling is likely to occur?

The buckling equation is: F= ((∏^2)*E*I)/(K*L)^2

E is the modulus, I is the area moment of inertia, K is the buckling coefficient, and L is the length of the column.

the mass moment of inertia for a hollow tube is;

(using meters)

I = (0.08^4-0.06^4)∏/64 = 1.37 x 10^-6 m^4

for the force, F, that will cause yielding.

The equation is:

σ= F/A

The cross sectional area of the column is:

Need to convert MN/m^2 to GN/m^2 by multiplying by 10^-3.

Therefore, F = Aσ = 0.02 x 141 x 10^-3 = 3.08x10-4 GN

The value of K for fixed-fixed end conditions is 0.5

Therefore, rearange the equation and solve for L

L= (SQRT) ((∏^2)*E*I)/F*k^2 = 5.93 m

This means, if the column is longer than 5.93 meters, it will buckle due to slenderness. Otherwise, if it is shorter than 5.93 meters, it will not displace out of plane and fail in yielding.

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

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# Homework Help: Column buckling answer confirmation

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