Buckling and column effective length question

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SUMMARY

The discussion focuses on calculating the minimum length of a fixed column where buckling is likely to occur, using specific parameters: an outer diameter of 100mm, an inner diameter of 60mm, Young's modulus of 250 GN/m², and a yield stress of 180 MN/m². The calculations involve determining the effective length (Le) using the equations K = 0.5 sqrt(R² + r²), ESR = sqrt(π² E / yield stress), and ESR = Le / k. The final result indicates that the minimum length for buckling is 6.84 meters, confirming the accuracy of the calculations presented.

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fuofa
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Homework Statement


If I have a column, fixed at both ends, i am aiming to work out the minimum length where buckling is likely to occur.
I know this is a similar question to that asked before, however please bear with me.
Column outer diameter 100mm, inner diameter 60mm
Youngs modulus E=250GNm^-2
Yield stress = 180MNm^-2

Homework Equations


1. K = 0.5 sqrt (R^2 + r^2)
2. ESR = sqrt pi^2 E/ yield stress
3. ESR = Le/k

The Attempt at a Solution



To find K using the above equation I have taken the radius 0.5 x sqrt (0.05^2 + 0.03^2) = 0.0292
Then to find the ESR I have sqrt(pi^2 x 250000000000 / 180000000) = 117.080
Changing the third equation from above for Le I have ESR x K = Le (117.080 x 0.0292) = 3.419m
Given that the column is fixed at both ends I have multiplied this by 2 and reach the minimum length of the column at which buckling is likely to occur to be 6.84 m - is that correct please?
 
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fuofa said:

Homework Statement


If I have a column, fixed at both ends, i am aiming to work out the minimum length where buckling is likely to occur.
I know this is a similar question to that asked before, however please bear with me.
Column outer diameter 100mm, inner diameter 60mm
Youngs modulus E=250GNm^-2
Yield stress = 180MNm^-2

Homework Equations


1. K = 0.5 sqrt (R^2 + r^2)
2. ESR = sqrt pi^2 E/ yield stress
3. ESR = Le/k

The Attempt at a Solution



To find K using the above equation I have taken the radius 0.5 x sqrt (0.05^2 + 0.03^2) = 0.0292
Then to find the ESR I have sqrt(pi^2 x 250000000000 / 180000000) = 117.080
Changing the third equation from above for Le I have ESR x K = Le (117.080 x 0.0292) = 3.419m
Given that the column is fixed at both ends I have multiplied this by 2 and reach the minimum length of the column at which buckling is likely to occur to be 6.84 m - is that correct please?

Yes, this looks correct.
 
Thank you!
 

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