By what factor would the energy carried by the rope change

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SUMMARY

The energy carried by a rope is directly proportional to the square of its amplitude. In this discussion, the initial amplitude is 15 mm, and the new amplitude is 20 mm. The factor by which the amplitude changes is calculated as the ratio of the new amplitude to the old amplitude, which is 20 mm / 15 mm. Consequently, the energy carried by the rope changes by a factor of (20/15)^2, resulting in an increase in energy by a factor of approximately 1.78.

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Homework Statement


The amplitude of a wave in a rope is [tex]15 \ mm[/tex]. If the amplitude were changed to [tex]20 \ mm[/tex]. Keeping the frequency the same, by what factor would the energy carried by the rope change?

Homework Equations


[tex]intensity \propto (amplitude)^2[/tex]

The Attempt at a Solution


[tex]amplitude_1 = 15 \times 10^{-3} \ m[/tex]
[tex]amplitude_2 = 20 \times 10^{-3} \ m[/tex]

What to do next:confused:
 
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First, by what factor does the amplitude change?

One consequence of the equation you wrote is that

[tex]\frac{I_2}{I_1} = (\frac{A_2}{A_1})^2[/tex]
 

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