Cal III/ Multi-V (vector notation troubles)

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SUMMARY

The discussion centers on calculating the magnitude of the vector expression ||3A - B||, where vector A is defined as A = i + j - k and vector B as B = i - j + k. The user initially misunderstands the notation of the double bars, thinking it relates to finding a normal vector, but it is clarified that it simply denotes the magnitude of the vector. The correct approach involves using the formula for magnitude, which is the square root of the sum of the squares of the vector components, leading to the final result of 6.

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Homework Statement


Given vector A = i + j - k and vector B= i - j + k, calculate ||3A-B||.

My work can be found here (I am not literate in Latex markups):
http://img714.imageshack.us/img714/732/sixhomeworkproblems001.jpg

I am unfamiliar with the notation of the double bars surrounding this vector combination. I think, and I say that very loosely, that it means to find the normal vector to the plane. If I could get some clarification for that, then I don't think the problem should be too difficult.

Homework Equations


Uncertain of problem notation.

The Attempt at a Solution


http://img823.imageshack.us/img823/8554/attempt001.jpg
 
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You're really close. All you have to do is find the magnitude of that vector. The equation for that is the square root of the sum of all of its components squared.
Sqrt(a^2+b^2+c^2).
 
Wow. So all the question asks for is the magnitude?

[tex]sqrt(36)[/tex]=6
 

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