Grad of a function in vector notation

In summary, the conversation discusses the computation of the gradient of a function in vector notation and the confusion about the difference between gradient of scalars and vectors. The solution is clarified to be the divergence of q, denoted as ∇.q.
  • #1
leoflindall
41
0

Homework Statement



q = xy[tex]^{2}[/tex]z i + y[tex]^{2}[/tex]xz j + e[tex]^{2z}[/tex] k

Homework Equations



Grad (f) = (fx,fy,fz), where fx, fy, fz are partial derivatives


The Attempt at a Solution



I am Comptent at computing the gradient of a function, however i do not see how to do this when in vector notation. Any Help would be greatly appreciated!

Thank You
 
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  • #2
Hi leoflindall! :smile:

(have a del: ∇ and try using the X2 tag just above the Reply box :wink:)
leoflindall said:
I am Comptent at computing the gradient of a function, however i do not see how to do this when in vector notation. Any Help would be greatly appreciated!

We have gradient of scalars, not of vectors.

Are you sure it isn't .q, the divergence of q ?
 
  • #3
Of course i did, i tihnk it must be the late hour but i was just being silly! Thank you for your help!
 

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