Grad of a function in vector notation

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SUMMARY

The discussion centers on computing the gradient of a vector function defined as q = xy²z i + y²xz j + e²z k. Participants clarify that gradients apply to scalar functions, not vector functions, and suggest that the correct operation for vector fields is the divergence, represented as ∇·q. The confusion arises from the notation and the late hour, leading to a humorous exchange about the misunderstanding.

PREREQUISITES
  • Understanding of vector calculus concepts, specifically gradients and divergences.
  • Familiarity with partial derivatives and their notation.
  • Knowledge of vector notation and operations in multivariable calculus.
  • Basic competency in mathematical functions and their representations.
NEXT STEPS
  • Study the properties and applications of vector fields in physics and engineering.
  • Learn about the divergence operator and its significance in vector calculus.
  • Explore the relationship between gradients and scalar fields in multivariable calculus.
  • Practice computing gradients and divergences using various vector functions.
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Students and professionals in mathematics, physics, and engineering who are learning about vector calculus and need clarification on the operations involving vector functions.

leoflindall
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Homework Statement



q = xy[tex]^{2}[/tex]z i + y[tex]^{2}[/tex]xz j + e[tex]^{2z}[/tex] k

Homework Equations



Grad (f) = (fx,fy,fz), where fx, fy, fz are partial derivatives


The Attempt at a Solution



I am Comptent at computing the gradient of a function, however i do not see how to do this when in vector notation. Any Help would be greatly appreciated!

Thank You
 
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Hi leoflindall! :smile:

(have a del: ∇ and try using the X2 tag just above the Reply box :wink:)
leoflindall said:
I am Comptent at computing the gradient of a function, however i do not see how to do this when in vector notation. Any Help would be greatly appreciated!

We have gradient of scalars, not of vectors.

Are you sure it isn't .q, the divergence of q ?
 
Of course i did, i tihnk it must be the late hour but i was just being silly! Thank you for your help!
 

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