Calc II Integral Homework Solving Attempts

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The discussion focuses on solving the indefinite integral of (x^2+5x+16)/sqrt(x^2-16x) using trigonometric substitution. The initial attempt involved setting x = 4 sec x, which complicated the expression. A suggestion was made to complete the square for the expression in the radical, transforming it into a more manageable form. This approach involves rewriting the denominator as sqrt((x-8)^2 - 64) and then using a hyperbolic substitution. The conversation emphasizes the importance of simplifying the integral before applying substitutions.
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Homework Statement



Indefinite integral of (x^2+5x+16)/sqrt(x^2-16x)

Homework Equations



Trig substitution and identities.


The Attempt at a Solution



I've tried setting x = 4 sec x but it has turned into a mess, and I really don't know where to go now. Using x, I'm left with

(16sec^2(x)+20sec(x)+64sec(x)tan(x))/sqrt(16sec^2(x)-64sec(x))

But I'm not even sure if I've done this right. Any help would be much appreciated! Thanks!
 
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sydneyfranke said:

Homework Statement



Indefinite integral of (x^2+5x+16)/sqrt(x^2-16x)

Homework Equations



Trig substitution and identities.


The Attempt at a Solution



I've tried setting x = 4 sec x but it has turned into a mess, and I really don't know where to go now. Using x, I'm left with

(16sec^2(x)+20sec(x)+64sec(x)tan(x))/sqrt(16sec^2(x)-64sec(x))

But I'm not even sure if I've done this right. Any help would be much appreciated! Thanks!
You probably did your trig substitution too soon.

For the expression in the radical, complete the square to get x2 - 16x + 64 - 64. This factors into (x - 8)2 - 64, which you can turn into u2 - 82.
 
Last edited:
I would work on the denominator first, so:
<br /> \sqrt{x^{2}-16x}=\sqrt{(x-8)^{2}-64}<br />
and then let:
<br /> x=8+8\cosh u<br />
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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