Calculate Azimuth of BC: Homework Help

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SUMMARY

The discussion focuses on calculating the azimuth of segment BC based on the provided azimuth of segment AB, which is given as 126°55'17''. The user calculated the back azimuth to be 306°55'17'' by adding 180° to the azimuth of AB. The confusion arises from the relationship between the angles, particularly why the azimuth of BC would exceed that of AB. The user also notes the presence of a deceptive wider arc around angle B, which complicates the interpretation of the angles involved.

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Homework Statement


In the attachment. Need to calculate azimuth of BC.

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The Attempt at a Solution


I don't understand why the azimuth of AB would be given as 126 degrees when it is almost a complete revolution of 360 degrees. I calculated the back azimuth which would be 306°55'17''. (126°55'17"+180°=306°55'17'').I added the interior B angle and got 178°18'58". But how could the of BC be greater then AB? Please help me. Thanks!
 

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There is a B arc labelled angle B and then there is a wider arc around that B arc. That wider arc is completely deceptive.

The 126 55 17 is a bearing from N.
 
Thanks for replying. Does that mean my answer is correct?
 

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