Why is the azimuth of BC greater than the azimuth of AB?

[coolguy16]

Homework Statement

In the attachment. Need to calculate azimuth of BC.

Homework Equations

The Attempt at a Solution

I don't understand why the azimuth of AB would be given as 126 degrees when it is almost a complete revolution of 360 degrees. I calculated the back azimuth which would be 306°55'17''. (126°55'17"+180°=306°55'17'').I added the interior B angle and got 178°18'58". But how could the of BC be greater then AB? Please help me. Thanks!

 

[.Scott]

There is a B arc labelled angle B and then there is a wider arc around that B arc. That wider arc is completely deceptive.

The 126 55 17 is a bearing from N.

 

[coolguy16]

Thanks for replying. Does that mean my answer is correct?