Calculate calories burned from lifting weights?

  • Thread starter Thread starter enanthate
  • Start date Start date
  • Tags Tags
    Calories Lifting
AI Thread Summary
Calculating calories burned from lifting weights involves a formula that considers the weight lifted, distance traveled, gravitational constant, and number of repetitions, followed by adjusting for human muscle efficiency, typically between 18-26%. However, this calculation is overly simplistic as it does not account for energy expenditure during static holds or the eccentric phase of lifting, where muscles still burn calories despite mechanical work being done by gravity. Discussions also highlight the importance of recognizing that "calories" in food energy are technically "kcal" in mechanical terms. Furthermore, body weight and individual efficiency in lifting specific weights can affect overall caloric burn, suggesting that a heavier individual may burn fewer calories relative to their body weight when lifting the same weight as a lighter person. A more comprehensive approach is needed for accurate caloric expenditure calculations during weightlifting.
enanthate
Messages
13
Reaction score
1
Hi all,

So I was thinking about how you could calculate the calories burned when lifting weights. The actual energy requirement should be simple enough if I'm not mistaken :

Amount of weight in kg * distance traveled per repetition in m * g constant * number of reps = Joule expenditure

Then take this and divide it by 8-26% efficiency for human muscle.

Does this sound right for a simple, general caloric requirement calculation or am I missing something I should be taking into account

Thanks for any input
 
Physics news on Phys.org
I meant18-26%

enanthate said:
Hi all,

So I was thinking about how you could calculate the calories burned when lifting weights. The actual energy requirement should be simple enough if I'm not mistaken :

Amount of weight in kg * distance traveled per repetition in m * g constant * number of reps = Joule expenditure

Then take this and divide it by 8-26% efficiency for human muscle.

Does this sound right for a simple, general caloric requirement calculation or am I missing something I should be taking into account

Thanks for any input
 
1. You need to be aware that the "calories" used in categorizing the amount of "energy" in food and in body functions is actually "kcal" in mechanics.

2. Even when the weight is not moving, by holding it up, you are still burning calories, since the muscles have to contract and uses up energy. Yet, mechanically, this does no work.

3. Similarly, on the downstroke of weight lifting, depending on how slow the weight is moved, energy is still burnt by the muscles, even if mechanically, work is done by the gravitational field.

I'm sure physiotherapists have ways of estimating this, but what you did appeared to be too simplistic and not take into account a lot of other significant factors.

Zz.
 
I agree that it is very simplistic. But that's what I'm looking for :) just want to make sure my thinking is right. In any case this calculation will be on the low side for the reasons you mention
ZapperZ said:
1. You need to be aware that the "calories" used in categorizing the amount of "energy" in food and in body functions is actually "kcal" in mechanics.

2. Even when the weight is not moving, by holding it up, you are still burning calories, since the muscles have to contract and uses up energy. Yet, mechanically, this does no work.

3. Similarly, on the downstroke of weight lifting, depending on how slow the weight is moved, energy is still burnt by the muscles, even if mechanically, work is done by the gravitational field.

I'm sure physiotherapists have ways of estimating this, but what you did appeared to be too simplistic and not take into account a lot of other significant factors.

Zz.
ZapperZ said:
1. You need to be aware that the "calories" used in categorizing the amount of "energy" in food and in body functions is actually "kcal" in mechanics.

2. Even when the weight is not moving, by holding it up, you are still burning calories, since the muscles have to contract and uses up energy. Yet, mechanically, this does no work.

3. Similarly, on the downstroke of weight lifting, depending on how slow the weight is moved, energy is still burnt by the muscles, even if mechanically, work is done by the gravitational field.

I'm sure physiotherapists have ways of estimating this, but what you did appeared to be too simplistic and not take into account a lot of other significant factors.

Zz.
 
Is your 18-24% efficiency just for the muscles moving the weight? And this is for anyone, because I've had the same question as enanthate above, and maybe there is just no way to figure it out...but how do you calculate as a percentage of a 1RM or even vs your body weight.
I guess I'm asking the efficiency in which someone moves a specific weight. Example 20 squats at 50lb for a 200lb man vs a 100lb man, assuming everything else is the same. From a mechanical standpoint the 50lb weight requires the same amount of energy to move it for each person, but in reality does the 200lb man actually burn less calories since it's a smaller percentage of his body weight, ie he's more efficient?
 
I have recently been really interested in the derivation of Hamiltons Principle. On my research I found that with the term ##m \cdot \frac{d}{dt} (\frac{dr}{dt} \cdot \delta r) = 0## (1) one may derivate ##\delta \int (T - V) dt = 0## (2). The derivation itself I understood quiet good, but what I don't understand is where the equation (1) came from, because in my research it was just given and not derived from anywhere. Does anybody know where (1) comes from or why from it the...
Back
Top