Calculate Charging Current of Generator & Battery

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    Charging Current
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Discussion Overview

The discussion revolves around calculating the charging current of a generator connected to a battery, given their respective internal resistances. Participants explore the application of Ohm's law and Kirchhoff's laws in this context, focusing on the circuit configuration and voltage differences.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant asks how to calculate the charging current given a 30V generator and a 24V battery, along with their internal resistances.
  • Another participant suggests using Ohm's law, indicating that the potential difference and resistance can be used to find the current flow.
  • A participant describes the circuit configuration and expresses uncertainty about whether to subtract or add the voltages to find the total voltage affecting the charging current.
  • One participant emphasizes the importance of visualizing the circuit and mentions that there is a total of six ohms of resistance between the two voltage sources.
  • Another participant agrees with the use of Kirchhoff's second law but points out an error in the initial equation proposed by the original poster.

Areas of Agreement / Disagreement

Participants express differing views on the approach to calculating the charging current, with some advocating for a straightforward application of Ohm's law while others suggest a more complex analysis involving Kirchhoff's laws. No consensus is reached on the best method to use.

Contextual Notes

Participants have not fully resolved the implications of the internal resistances on the overall circuit behavior, and there are uncertainties regarding the correct application of Kirchhoff's laws in this scenario.

nemesis24
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Charging current??

i have a question that says a generator is charging a normal battery the internal resistance of the generator and battery are given, and i must calculate the charging current how might this be done?

generator is 30v with 4 ohm internal resistance.
battery is 24v with a internal resistance of 2 ohms.

thanks in advance
 
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This, at it's most simple, is just ohm's law.
You know the potential difference in the circuit and the resistance in the circuit therefore you can calculate the current flow.

Redraw the circuit lumping all the voltage sources together and resistances together and you should see how to work it out.

Or were you wanting it a chemical level?
 
no chemical level, its just a generator pointing up with a resistance on top of it, and on the right side a resistor on top and a battery at the bottom (with the positive side facing up) and its all connected in series. and its asking 4 the charging current so i thought it may be asking the exact current needed for a 30v generator to charge a 24v battery. i was thinking of using kirchhoffs 2nd law and i got the equation 30-24 = 2I + I (not sure if its right). can i use this or if your method best?
 
You're making this too complicated, nemesis24. Draw a picture. It'll contain two voltage sources (one 30V, one 24V), with a total of six ohms of resistance between them.

That's six volts dropped across six ohms... use Ohm's law to find the current.

- Warren
 
so i take it that the two voltages would be substracked as it is the charging current. or would it add to give the total voltage?
 
You're thinking about it too much, still.

One one side of this combined six ohm resistor, you have 30V. On the other side, you have 24V. There is, thus, 6V across the resistor. 6V across a 6 ohm resistor gives...

- Warren
 
nemesis24 said:
... its just a generator pointing up with a resistance on top of it, and on the right side a resistor on top and a battery at the bottom (with the positive side facing up) and its all connected in series. and its asking 4 the charging current so i thought it may be asking the exact current needed for a 30v generator to charge a 24v battery. i was thinking of using kirchhoffs 2nd law and i got the equation 30-24 = 2I + I

Actually you are on the right track here, using http://www.physics.uoguelph.ca/tutorials/ohm/Q.ohm.KVL.html (The total voltage around a closed path equals zero). Except you have an error in your equation 30-24 = 2I + I [hint: What did you say was the internal resistance (Rs) on the generator? ]
 

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