Calculate Current in a 50 Ohm Resistor from Half Wave Rectified Voltage

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To calculate the current in a 50 Ohm resistor from a half-wave rectified voltage described by v(t)=100.sin(X), first determine the average voltage by integrating the absolute value of the sine wave over one half-cycle and dividing by its length, which is π. This average voltage can then be used to find the average current using Ohm's Law. Additionally, the RMS value of the current can be calculated from the RMS voltage of the rectified signal. The discussion emphasizes the importance of using the absolute value of the sine function for accurate calculations. Understanding these steps is crucial for solving the problem effectively.
cleas001
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im stuck on this question and was wondering if anyone could help point me in the right direction:
a half wave rectified voltage is described by: v(t)=100.sinX
(that X is mean to be theta)
when applied to a 50 ohm resistor find the average and rms values of the current.


thanks an help is much appreciated...
a stuggling student
 
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The key word there is average. The average value of any curve equals the area of that curve divided by its length. In order words, take the integral of the sine wave from 0 to pi then divide by the length of the curve which is pi in this case. Once you find the average voltage it is possible to find the average current using ohms law.
 
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okay i will certainly give that a good try thanks
 
cleas001 said:
im stuck on this question and was wondering if anyone could help point me in the right direction:
a half wave rectified voltage is described by: v(t)=100.sinX
No, after an ideal half-wave rectification, you will have v(t) = 100 |sin(x)|. Be sure to average the absolute value version of the excitation. Hint -- You can calculate the average for a half-cycle of the sine first...
 
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