Calculate Dynamo Max Power Output

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SUMMARY

The discussion focuses on calculating the theoretical maximum power output of a small DC dynamo using the formula P=V^2/R, where V is the measured voltage. Participants suggest measuring the internal resistance of the dynamo to apply the maximum power theorem, which states that maximum power occurs when load resistance equals internal resistance. Additionally, using the formula P=IV and graphing current (I) against various external loads is recommended to determine optimal performance without damaging the dynamo.

PREREQUISITES
  • Understanding of electrical power formulas, specifically P=V^2/R and P=IV.
  • Knowledge of internal resistance measurement techniques for DC generators.
  • Familiarity with the maximum power theorem in electrical circuits.
  • Basic skills in graphing and analyzing electrical load data.
NEXT STEPS
  • Research methods for measuring internal resistance of DC generators.
  • Learn about the maximum power theorem and its applications in circuit design.
  • Explore techniques for safely testing electrical loads on dynamo systems.
  • Investigate tools for graphing electrical performance data, such as Excel or MATLAB.
USEFUL FOR

Electrical engineers, hobbyists working with DC generators, and anyone interested in optimizing power output in dynamo systems.

El_Guapo
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Hi,
I have a small DC dynamo (with no spec sheet) which i digitally sample to find it's voltage at any given time. I want to display theoretical max power output, how can I calculate this?

Can I use P=V^2/R where V is measured. How do I calculate R? I read a wikipedia article which says to calculate the ac resistance of the dynamo and take the load as equal to internal resistance of the generator (max power theorem.) Will this work...I'm not too sure what I'm doing on this one. Thanks.
 
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El_Guapo said:
Hi,

Can I use P=V^2/R where V is measured.

I would use P=IV, and graph IV vs. various loads (external resistors). But be aware that very low (or no) resistance could result in very high current outputs, and might "fry" your dynamo.
 
But I know the maximum power will occur when the load resistance is equal to the internal resistance so I guess I could just measure the current flowing in this circuit. I'm just after a single number to act as a conversion factor to kw/h.
 

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