Calculate Fountain Power for a 28.8m Stream Using Bernoulli's Equation

  • Thread starter Thread starter kitty9035
  • Start date Start date
  • Tags Tags
    Power
Click For Summary

Homework Help Overview

The problem involves calculating the power required for a fountain to send a stream of water 28.8 meters high, given the diameter of the stream and the acceleration due to gravity. The context is rooted in fluid dynamics, specifically applying Bernoulli's equation.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss using Bernoulli's equation to find pressure and relate it to work and power. There are questions about the necessity of finding time and the correct application of formulas related to work and power. Some participants suggest alternative approaches to calculating force and velocity.

Discussion Status

The discussion is active, with participants exploring different methods to approach the problem. Some guidance has been offered regarding the relationships between pressure, force, and velocity, but there is no explicit consensus on the best path forward.

Contextual Notes

Participants are navigating through the constraints of the problem, including the need for pressure and velocity, as well as the implications of using different equations. There is an acknowledgment of missing information regarding pressure and the need for further clarification on time calculations.

kitty9035
Messages
17
Reaction score
0

Homework Statement


A fountain sends a stream of water 28.8 m up into the air. The acceleration of gravity is 9.8. IF the base of the stream is 4.38 cm in diameter, what power is required to send the water to this height?


Homework Equations





The Attempt at a Solution



I was thinking maybe using bernoulli's equation to find the pressure and plug into to the formula work=pressure x volume. Then plug the answer for work into power=work/delta t.

Then i was thinking how do u find the time.. so i used the equation t= the square root of 2gh.

Is my though process correct? Any hints?? tHANKS IN ADVANCE
 
Physics news on Phys.org
work=pressure x volume

i believe work = pressure * velocity
are u sure u need to find the time
 
Power = Force * Velocity as well =).

You have the right idea though that you would be using an equation where you get a square root of 2g(delta y). But the problem is that your equation isn't solving for time! Think about what you need =).

Pressure = Force / Area; use basic algebra to solve for Force. But problem, you don't have the pressure =). Solve for it.

You know the "rho" of water (density). There's an equation to get a pressure =).
 
Last edited:
I solved for the Force by finding the mass and multiplying it by 9.8. Now I'm having trouble finding the velocity
 

Similar threads

  • · Replies 9 ·
Replies
9
Views
3K
Replies
19
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 74 ·
3
Replies
74
Views
16K
  • · Replies 8 ·
Replies
8
Views
5K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 15 ·
Replies
15
Views
11K
  • · Replies 29 ·
Replies
29
Views
5K