Calculate Gate Source, Drain Current, and Source Voltage of a JFET

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The discussion focuses on calculating the gate voltage, source voltage, and drain current of a JFET. The user initially miscalculated the gate voltage, thinking it was -7V instead of the correct -4V. They clarified that the voltage across the potential divider R1 and R2 is 20V, leading to a voltage of 6V across R2. The conversation also touches on the need for specific equations related to JFET parameters like ka', W/L, and Ka. Ultimately, the user resolved their confusion and expressed hope for a good test outcome.
DODGEVIPER13
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Homework Statement


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Homework Equations


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The Attempt at a Solution


So what I started with is Vg=(R2/(R1+R2))Vdd - 10 = -7 Volts this is incorrect though I was told it is -4 V what did I do
 

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Theoretically after I solve for this I would get Kn and Id. Then I would set up an equation to find Vgs.
 
The voltage across the potential divider R1+R2 is 20V. So the voltage across R2 is..

20 * R2/(R1+R2) = 6V

So the gate is 6V above the -10V rail which is -4V.
 
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Likes SShashank117 and DODGEVIPER13
Thanks man
 
What equation were you given that includes ka', W/L and Ka? These are not standard terms in a JFET model so you need to give us your equation(s).
 
Oh yah I got it all figured out man thanks just had the test too hope I did well
 

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