# Calculate Gate Source, Drain Current, and Source Voltage of a JFET

1. Nov 29, 2013

### DODGEVIPER13

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution
So what I started with is Vg=(R2/(R1+R2))Vdd - 10 = -7 Volts this is incorrect though I was told it is -4 V what did I do

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2. Nov 29, 2013

### DODGEVIPER13

Theoretically after I solve for this I would get Kn and Id. Then I would set up an equation to find Vgs.

3. Nov 29, 2013

### CWatters

The voltage across the potential divider R1+R2 is 20V. So the voltage across R2 is..

20 * R2/(R1+R2) = 6V

So the gate is 6V above the -10V rail which is -4V.

4. Nov 29, 2013

### DODGEVIPER13

Thanks man

5. Nov 30, 2013

### rude man

What equation were you given that includes ka', W/L and Ka? These are not standard terms in a JFET model so you need to give us your equation(s).

6. Dec 4, 2013

### DODGEVIPER13

Oh yah I got it all figured out man thanks just had the test too hope I did well