DODGEVIPER13 Messages 668 Reaction score 0 Thread starter Nov 29, 2013 #1 Homework Statement Uploaded Homework Equations Uploaded The Attempt at a Solution So what I started with is Vg=(R2/(R1+R2))Vdd - 10 = -7 Volts this is incorrect though I was told it is -4 V what did I do Attachments electronics_Study.PNG 16.8 KB · Views: 2,347
Homework Statement Uploaded Homework Equations Uploaded The Attempt at a Solution So what I started with is Vg=(R2/(R1+R2))Vdd - 10 = -7 Volts this is incorrect though I was told it is -4 V what did I do
DODGEVIPER13 Messages 668 Reaction score 0 Nov 29, 2013 #2 Theoretically after I solve for this I would get Kn and Id. Then I would set up an equation to find Vgs.
Theoretically after I solve for this I would get Kn and Id. Then I would set up an equation to find Vgs.
CWatters Science Advisor Homework Helper Gold Member Messages 10,546 Reaction score 2,324 Nov 29, 2013 #3 The voltage across the potential divider R1+R2 is 20V. So the voltage across R2 is.. 20 * R2/(R1+R2) = 6V So the gate is 6V above the -10V rail which is -4V.
The voltage across the potential divider R1+R2 is 20V. So the voltage across R2 is.. 20 * R2/(R1+R2) = 6V So the gate is 6V above the -10V rail which is -4V.
rude man Science Advisor Insights Author Messages 8,032 Reaction score 870 Nov 30, 2013 #5 What equation were you given that includes ka', W/L and Ka? These are not standard terms in a JFET model so you need to give us your equation(s).
What equation were you given that includes ka', W/L and Ka? These are not standard terms in a JFET model so you need to give us your equation(s).
DODGEVIPER13 Messages 668 Reaction score 0 Dec 4, 2013 #6 Oh yah I got it all figured out man thanks just had the test too hope I did well