Calculate kinetic energy transferred

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Homework Help Overview

The discussion revolves around calculating the kinetic energy transferred to a fluid during an experiment, specifically focusing on questions related to the mass of the fluid before and after the experiment and the velocity at which it exits the bottle.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the use of the kinetic energy formula and question the relevance of the velocity of the fluid as it leaves the bottle. There are discussions about calculating the maximum horizontal distance and the implications of using rounded values in calculations. Some participants express uncertainty about the correct approach to determine the time of flight and the appropriate equations of motion to use.

Discussion Status

Participants are actively engaging with the problem, offering guidance on avoiding rounding errors and suggesting the use of unrounded values for accuracy. There is a recognition of the need to clarify the mass of the ejected fluid and the initial and final velocities involved in the kinetic energy calculations. Multiple interpretations of the problem setup are being explored, but no consensus has been reached.

Contextual Notes

There is mention of homework constraints, such as the requirement to use equations of motion rather than the range equation, and the need to clarify the mass of the fluid that was ejected from the bottle.

  • #31
gneill said:
Well, I think you meant parabola rather than hyperbola, but yes, that's about it.
Oh yes that's what I meant! Thank you so much for helping me this evening, we got there in the end :) I really appreciate it!
 
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  • #32
gneill said:
Well, I think you meant parabola rather than hyperbola, but yes, that's about it.
Wait, but the vertical velocity does change because of acceleration due to gravity?
 
  • #33
Nicaragua said:
Wait, but the vertical velocity does change because of acceleration due to gravity?
Yes.
 
  • #34
gneill said:
Yes.
I am really sorry but I am re-visiting this question and do not understand it. Can you please explain to me how you work out the kinetic energy transferred when leaving the bottle? Do you use 1/2 m v^2 with v = the final velocity of the fluid (7.5 m/s^2)?
 
  • #35
Nicaragua said:
I am really sorry but I am re-visiting this question and do not understand it. Can you please explain to me how you work out the kinetic energy transferred when leaving the bottle? Do you use 1/2 m v^2 with v = the final velocity of the fluid (7.5 m/s^2)?
Not the final velocity, the initial velocity that the fluid has as it leaves the bottle. That's the 7.5 m/s value. Yes, you apply that speed and the total mass that's been given that speed to the kinetic energy formula.

The final velocity would be the speed of the fluid as it hits the ground at the end of its trajectory.
 
  • #36
gneill said:
Not the final velocity, the initial velocity that the fluid has as it leaves the bottle. That's the 7.5 m/s value. Yes, you apply that speed and the total mass that's been given that speed to the kinetic energy formula.

The final velocity would be the speed of the fluid as it hits the ground at the end of its trajectory.
So is the total mass that has been given the velocity of 7.5 ms^-2 2.24 kg?
 
  • #37
Nicaragua said:
So is the total mass that has been given the velocity of 7.5 ms^-2 2.24 kg?
Review posts #12 and #13.
 

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