Calculate kinetic energy transferred

[Nicaragua]

Well, I think you meant parabola rather than hyperbola, but yes, that's about it.

Oh yes that's what I meant! Thank you so much for helping me this evening, we got there in the end :) I really appreciate it!

 

[Nicaragua]

Well, I think you meant parabola rather than hyperbola, but yes, that's about it.

Wait, but the vertical velocity does change because of acceleration due to gravity?

 

[gneill]

Wait, but the vertical velocity does change because of acceleration due to gravity?

Yes.

 

[Nicaragua]

Yes.

I am really sorry but I am re-visiting this question and do not understand it. Can you please explain to me how you work out the kinetic energy transferred when leaving the bottle? Do you use 1/2 m v^2 with v = the final velocity of the fluid (7.5 m/s^2)?

 

[gneill]

I am really sorry but I am re-visiting this question and do not understand it. Can you please explain to me how you work out the kinetic energy transferred when leaving the bottle? Do you use 1/2 m v^2 with v = the final velocity of the fluid (7.5 m/s^2)?

Not the final velocity, the initial velocity that the fluid has as it leaves the bottle. That's the 7.5 m/s value. Yes, you apply that speed and the total mass that's been given that speed to the kinetic energy formula.

The final velocity would be the speed of the fluid as it hits the ground at the end of its trajectory.

 

[Nicaragua]

Not the final velocity, the initial velocity that the fluid has as it leaves the bottle. That's the 7.5 m/s value. Yes, you apply that speed and the total mass that's been given that speed to the kinetic energy formula.

The final velocity would be the speed of the fluid as it hits the ground at the end of its trajectory.

So is the total mass that has been given the velocity of 7.5 ms^-2 2.24 kg?

 

[gneill]

So is the total mass that has been given the velocity of 7.5 ms^-2 2.24 kg?

Review posts #12 and #13.