Calculate Local g on Small Planet: 3.70g Wire, 3.00kg Mass, 43.6ms Pulse

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To calculate the local gravitational acceleration (g) on a small planet, an astronaut uses a wire with a mass of 3.70 g and a length of 1.60 m, suspending a 3.00 kg mass from it. A pulse takes 43.6 ms to travel the length of the wire. The initial calculation attempted was g = length * mstring / (mweight * t^2), resulting in an incorrect value of 0.001. Participants in the discussion are questioning the inputs used in this formula to identify the error. Accurate calculations are essential for determining the correct value of g based on the given data.
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An astronaut on a small planet wishes to measure the local value of g by timing pulses traveling down a wire which has a large mass suspended from it. Assume that the wire has a mass of 3.70 g and a length of 1.60 m and that a 3.00 kg mass is suspended from it. A pulse requires 43.6 ms to traverse the length of the wire. Calculate the local g from these data. (You may neglect the mass of the wire when calculating the tension in it.)

I tried to solve the qustion by doing g= length * mstring/ ( mweight*t^2) and i got .001 but the answer is wrong
 
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Hi lulu16,


lulu16 said:
An astronaut on a small planet wishes to measure the local value of g by timing pulses traveling down a wire which has a large mass suspended from it. Assume that the wire has a mass of 3.70 g and a length of 1.60 m and that a 3.00 kg mass is suspended from it. A pulse requires 43.6 ms to traverse the length of the wire. Calculate the local g from these data. (You may neglect the mass of the wire when calculating the tension in it.)

I tried to solve the qustion by doing g= length * mstring/ ( mweight*t^2) and i got .001 but the answer is wrong


I don't see how you are getting 0.001 as your answer. What numbers are you putting into your formula?
 
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