Calculate Maximum Axial Force in Aluminum Bar

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SUMMARY

The discussion focuses on calculating the maximum axial force that an aluminum bar can withstand given an allowable stress of 200 MPa. The primary formula used is allowable stress = P/A, where P is the axial force and A is the cross-sectional area. Participants emphasize the importance of unit consistency and suggest reviewing relevant equations from textbooks to ensure accurate calculations. A valid attempt at solving the problem is encouraged to facilitate further discussion.

PREREQUISITES
  • Understanding of allowable stress and its calculation
  • Familiarity with the formula P = A × allowable stress
  • Knowledge of material properties of aluminum
  • Basic principles of mechanics of materials
NEXT STEPS
  • Review the mechanics of materials textbook for stress and strain concepts
  • Learn about calculating cross-sectional areas for different shapes
  • Study unit conversion techniques in engineering calculations
  • Explore examples of axial force calculations in structural engineering
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Mechanical engineers, structural engineers, students studying materials science, and anyone involved in the design and analysis of structural components.

anon00
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1. An Aluminum bar has the dimensions given in the attachment. if the allowable stress is 200MPa, determine the maximum axial force P allow that can be carried by the bar.

See attachment for the drawing

2. allowable stress=P/A, E=deformation/L, allowable stress=L/E


3. I attempted all of hte above. I am thinking something is missing.
 

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Your relevant equations are currently incorrect. Study your textbook, list relevant equations, and post a valid attempt.
 
Hi anon,
Welcome to the board.
anon00 said:
2. allowable stress=P/A
Solve for P and watch out for units. Remember that stress is simply a force transmitted through some area, analogous to presssure.
 

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