Calculate Minimum Horsepower to Drag 340 kg Box at 1.45 m/s

[Jo-AnneLi]

Homework Statement

What minimum horsepower must a motor have to be able to drag a 340 kg box along a level floor at a speed of 1.45 m/s if the coefficient of friction is 0.50?

Homework Equations

Power = Change in Energy/time = Work/time
Change in energy = Final energy - Initial energy
Work = Net Force x displacement
Force of Friction = Normal force x coefficient of friction = mg x coefficient of friction
Kinetic energy = 1/2 x m x v^2
Change in gravitational potential energy = mgh

The Attempt at a Solution

I know that we should always start with the equation Power = Work/time or Power = Change in energy/time, and then sub in values. The problem is that of the equations given above, none of them seem to work. We are not given displacement. I found the friction force = 1667.7 N but I'm unsure as to how to find net force. Kinetic energy = 357.425 J, but is that the initial/final energy and how do I find the other one?
I'm just really confused about this question...please help! You don't have to tell me the whole solution, just a hint would be nice.

 

[PhanthomJay]

Hint..there is no net force since the box is moving at constant velocity...so then what is the force being provided by the motor?
Hint 2: there is another formula for power equivalent to W/t...if W = Fd , then P = Fd/t...what is d/t?
Welcome to the Physics Forums!