Calculate N for 95% Confidence in Iodine in Sea Water

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To determine the minimum number of samples (N) needed for 95% confidence that the mean iodine concentration in sea water differs from the true value by no more than 2.0%, the relevant formula is n=(t^2)(s^2)/((u-x)^2). Given a mean of 46.43 μg/L, a standard deviation of 1.37 μg/L, and a margin of error of 0.02 (2%), the critical t-value for 95% confidence is approximately 1.96. The challenge arises from the dependence of the t-value on the degrees of freedom, which is not specified in the problem. Some participants suggest using a table to estimate N based on confidence levels. The discussion emphasizes the need for clarity on how to approach the calculation given the missing degrees of freedom information.
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Homework Statement



The determination of iodine in sea water gave a mean value of 46.43 μg/L and a sample standard deviation ss of 1.37 μg/L.

What is the minimum number of samples (N) which must be analyzed to have 95% confidence that the mean value differs from the true value by no more than 2.0%?

Homework Equations



u-x(bar)= +/- ts/rt(n) -------> n=(t^2)(s^2)/((u-x)^2)

The Attempt at a Solution



I know from the confident interval, the minimum at 95% is 1.96=t, s=1.37, e=0.02,
where am I going wrong?

Help please
 
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It's been awhile since I've done stats, but doesn't the t value depend on your degrees of freedom, which in turn depends on n?
 
Dopefish1337 said:
It's been awhile since I've done stats, but doesn't the t value depend on your degrees of freedom, which in turn depends on n?

It does but it is not given in the question. I don't know how possible it is to find the degree a freedom from the information given in the question. Any ideas folks?
 
For assumed N t is easy to calculate, isn't it? My stats are rusty as hell, but I think you can just prepare a table confidence vs N and check what N value is enough.

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