Calculate Potassium Clavulanate Mass in 5mL Oral Suspension

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The discussion focuses on calculating the mass of potassium clavulanate in a 5mL oral suspension of Augmentin ES, which contains 600mg of amoxicillin trihydrate and 7.07mg of potassium. The molar masses of potassium and potassium clavulanate are provided, along with the molecular formula for potassium clavulanate. Participants are attempting to determine the moles of potassium in the solution to find the mass of potassium clavulanate, while also calculating the volume needed to prepare a 100mL solution of 25ppm amoxicillin trihydrate. There is some confusion regarding the conversion of ppm to grams per liter and the necessary calculations to achieve the desired concentration. The discussion emphasizes the importance of understanding the relationship between concentration, volume, and mass in solution preparation.
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1. Augmentin ES is a powder containing amoxicillin tri hydrate and potassium clavulanate for oral suspension. Each 5mL of reconstituted aqueous oral suspension contains 600mg of amoxicillin trihydrate and 7.07mg of potassium.
Calculate the mass of potassium clavulanate in 5mL of the oral suspension.

What I have found so far
Molar Mass K: 39.1gmol-1
Molar Mass Potassium clavulanate: 237.251gmol-1
Molecular Formula potassium clavulante: C8H8KN05

I think I need to find the moles of K in the 5mL solution and go from there, but I'm not sure how to use the moles of K to solve the problem.
 
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You need the molecular formula for the potassium clavulanate.
 
Also I need to calculate the volume of this suspension required to prepare 100mL of 25ppm(w/v) solution of amoxicillin trihydrate. assume desnity of suspension = 1kgL-1

I'm not sure if what I have done is right:

to get 25ppm I ned 2.5x10-5g/L solute
Conc. of 5mL suspension = 120g/L

Volume required = m/c = 2.5x10-5g/120gL-1 = 2.08x10-8L
 
Seems right except for the first part, you need to multiply the 100 mL=0.010 L by the 25 ppm to get the amount in grams of amoxicillin trihydrate needed however you need to first convert the ppm to g/L assuming this is what they are referring to by "w/v".
 
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