Calculate Power from Water flow

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To calculate the theoretical maximum power from a water flow of 5 m/s in a 1 m² channel, the kinetic energy formula can be applied, but it must account for the exit velocity of the water, which cannot be zero. The total mechanical power into the turbine is determined by considering both pressure and gravitational energy, in addition to kinetic energy. The specific mechanical energy formula, P / ρ + gz + V²/2, should be multiplied by the mass flow rate to find the actual mechanical power. For a tidal flow application, a bi-directional shrouded axial turbine design is suggested, ensuring equal inlet and outlet sizes for efficiency. Accurate calculations require more details about the turbine's geometry and operational parameters.
waterturbine
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Hi,
I am interested in building a water turbine.
I am not sure how to calculate the theoretical maximum power that can be derived from a flow.

If I assume I have a flow of 5m/s and a channel (or pipe) 1m^2
then I have a volume of 5,000 l/s
How do I calculate the energy that this flow could transfer to a turbine (excluding losses)?

Ek = 1/2 * m * v^2
water has density 1 so mass of 5,000 l is 5,000 kg
Ek = 0.5 * 5,000 * 5^2
= 2,500 * 25
= 62,500 J
Power = 62.5kW ?

(This doesn't seem correct and it is over 40 years since I did any physics)
So maybe I am missing that the change in flow from input of 5m/s will not be to 0?

Am I missing anything else and is there some other method to resolve this?

Or do I have to determine the Differential pressure across the turbine (I do not have any specs for a turbine yet).

thanks
 
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waterturbine said:
Hi,
I am interested in building a water turbine.
I am not sure how to calculate the theoretical maximum power that can be derived from a flow.

If I assume I have a flow of 5m/s and a channel (or pipe) 1m^2
then I have a volume of 5,000 l/s
How do I calculate the energy that this flow could transfer to a turbine (excluding losses)?

Ek = 1/2 * m * v^2
water has density 1 so mass of 5,000 l is 5,000 kg
Ek = 0.5 * 5,000 * 5^2
= 2,500 * 25
= 62,500 J
Power = 62.5kW ?

(This doesn't seem correct and it is over 40 years since I did any physics)
So maybe I am missing that the change in flow from input of 5m/s will not be to 0?

Am I missing anything else and is there some other method to resolve this?

Or do I have to determine the Differential pressure across the turbine (I do not have any specs for a turbine yet).

thanks

It's almost that simple -- except (1) the water needs to exit the turbine at some speed, and (2) typically there are pressure and gravity terms that have to be accounted for. You haven't indicated a geometry (is this an axial-flow turbine with equal inlet and exit areas? a centrifugal turbine that extracts gravitational potential energy?) but in general you have to compute the total mechanical power flowing into the turbine and subtract the total mechanical power flowing out, and the difference is the shaft power. The specific mechanical energy (energy per unit mass) is

P / \rho +gz+V^2/2

You have to multiply this by the mass flow rate \dot{m} to get the mechanical power.

BBB
 
Hi BBB,
thanks for your response,
My applications is generating power from a tidal flow.
I am thinking of building a pontoon that will act as a bi directional shrouded Axial Turbine the inlet and outlet piping will be the same size.
 
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