gijoel
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Homework Statement
A wheelchair is pushed from the start to the finish from its resting phase and maintains a steady speed of 2m/s as the wheelchair travels to its destination, which is 25 m from the start. It takes 80.seconds to push the wheelchair from the start to the finish. What is the wheelchair's instantaneous speed when the wheelchair is 5m away from the end? (Forgive the crude drawing)
Homework Equations
V= d/t
Cir = 2 pi r
The Attempt at a Solution
There's one of two possible solutions. the speed is 2m/s because the question states that the wheelchair maintains a speed of 2m/s as its speed. But that doesn't sound quite right to me
Considering that the path is circular from the start to the finish. And the start and finish areas are 25 meters away from each other then the circular path is
Cir = 2 pi r
= 25 pi
= 79 meters long
Therefore we need to know the speed at 74 meters.
I could then say that V=d/t
so V = 79meter/80. seconds
= 0.99 m/second
But that doesn't seem to make sense. Am I over thinking this here?