Calculate Speed from Magnetic Pull Force

AI Thread Summary
The discussion revolves around calculating the speed of an object based on the force applied, specifically in the context of building a gauss gun. Newton's Second Law is referenced, emphasizing that force equals mass times acceleration, which helps determine how acceleration affects speed. A participant attempts to apply a 200-pound force to a 5-gram object, converting units and calculating speed, but realizes the need to use kilograms for mass. The conversation also touches on the complexities of magnetic force calculations, particularly for solenoids and railguns, while acknowledging challenges such as energy loss and heat. Overall, the participants share insights on physics principles and practical applications for their projects.
ironman13405
Messages
6
Reaction score
0
Okay i am new to this site so i figured this would be the best place to post this. I need an equation for my project i am working on.

I need an equation to find the speed of a object based off how much force is applied to it.

If this isn't clear enough i am welcome to give more information. Let me know
 
Physics news on Phys.org
F=ma
 
dacruick said:
F=ma

Could you explain? Yes i am very new to this..
 
The force(F) times the time for which it acts(t) is equal to the mass of the object(M) times the change of velocity of the object....Ft=M times velocity change.This is Newtons second law(as is F=Ma where a is acceleration)
 
Okay, sorry for the abrupt answer. This is Newton's Second Law. It states that mass of the object, multiplied by the acceleration of the object, is the Force applied.

But in a more practical sense, in the context that you want to use it this is essence.

If you apply a certain force to an object of mass 'm', the acceleration of that object will be the Force divided by mass. Your acceleration is measure in metres per second squared. So say your acceleration is 10 m/s². That means that your speed increases by 10 metres / second, per second. Or, every second that passes you have an increase of speed of 10 metres per second.

What is it that you are trying to do exactly?
 
dacruick said:
What is it that you are trying to do exactly?

I trying to show my friend how unlikely the idea he has is unlikely to work. Cause we both are going against each other (In order to get things done faster cause we want to beat each other) to make a gauss gun. I've made many coil designs some of which do amazing. But i have wasted a lot of money due to the lack of physics understandning. I am starting to get more into, and its helping greatly
 
coil designs as in springs? because if you have a spring Newton's second law has a change
 
No coils as in eletric.

So tell me if i got this right let's say i where to apply 200 pounds of force to a 5 gram object.

there are .2248 pounds in one Newton so that would be 889.67972 N then you would divide by 5 grams to make 177m/s and there are .44m/s in one MPH.. so thus it would be 395 MPH.. right?
 
mass is measured in SI units of kilograms. So youre going to have to divide that 5 by 1000. which will give your answer a couple more 0's
 
  • #10
but i forgot that your force is magnetic. you have current running through a coil and you want to figure out the force? you would have to do research on something called a solenoid then. which is going to make your calculations more complicated.
 
  • #11
I found the equation for for magnetic force

F=A*N*I (((mu0*N*)/(*(C)^2)) +(1/CL)

or you can do its for railgun

step one H = (N*I)/M

Step two B= (H*mu0)/A

Step three F= B*L*I

Step four speed = ((F*T)/W) *3.33
 
  • #12
Im not sure what all of your variables are, but the equations look good. give it a shot and see if your answer is plausible
 
  • #13
It gets more and more confusing the more i travel down the rabit hole. I am collecting data mostly from

http://www.intalek.com/AV/Railguns-Tim-Ventura-1994-2.pdf

My design is very apart from his but they follow the same concept. I am getting a major headache haha. Alot of my issues are the same repeating ones over and over again. Energy lost due to heat, the melting of wire due to heat, and etc. Let alone i don't know too much about eletrics... i am slowly finding out more and more.. i want to get it done haha. I have unlimited resources too, cause we are working through a school program, so it helps
 
  • #14
yeah electrics arent my forte either. I don't think i can help you any further. but good luck definitely
 
Back
Top