Calculate Steel Pipe Thickness for Oil Transportation | Safety Factor 1.5

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To calculate the minimum thickness of a steel pipe for oil transportation under a specified head and safety factor, the pressure is determined using the formula Pressure = head x density x gravity, resulting in 563,892 Pa. The thickness is then calculated as (safety factor x pressure x radius) / tensile strength, yielding a thickness of 4.2 mm. Concerns are raised about the plausibility of this thickness, with suggestions to consider using the diameter or circumference instead. Clarification is provided that the formula specifically requires the radius for the calculation. The discussion emphasizes the importance of correctly applying the formulas for accurate results.
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1. Homework Statement
A 1.2m diamater steel pipe carries oil of relative density 0.822 under a head of 70m of oil. What minimum thickness of 120MPa (yield stress) steel would be required for a safety factor of 1.5?


2. Homework Equations
Head = pressure/rho.g
thickness = (safety factor.Pressure.radius.)/Tensile Strength

3. The Attempt at a Solution
Okay so I worked out pressure by Pressure = head x density x gravity = 563892 Pa
Then I worked out the thickness by (1.5 x 562492 x 0.6)/120,000,000 = 0.0042 m = 4.2mm

Seems a bit too small to me, could someone please tell me if this is plausible or if not where I have gone wrong?
 
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Hey just a brainwave am I maybe supposed to use the diamater or circumference? Gives a more plausible seeming result
 
What formula are you using to calculate the stress in the pipe wall?
 
I didn't think that I needed to from the research I've done. The only formula I could find for minimum thickness is the one I posted above. Am I missing something?
 
If the formula says radius, you use the radius.
 

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