jumbogala
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Homework Statement
One side of a square has length 2.0 cm.
In three of the square's corners, there are point charges.
Top left corner: -1.0 nC (call this A)
Bottom left corner: 10 nC (call this B)
Bottom right corner: -1.0 nC (call this C)
The top right corner has no charge, and is labelled P.
What is the magnitude of the electric field at point P?
Homework Equations
Electric Field = KQ/r2
The Attempt at a Solution
Electric Field Due to A:
K(-1.0 x 10-9 C)/(0.02 m2) = -22475 N/C, left
Electric Field Due to C:
Same as above, but this time the direction is down
Electric Field Due to B:
First calculate the distance from B to P. This is 0.022+0.022 = 0.0008. Take the square root of 0.0008 to find 0.0282 m.
K(10 x 10-9 C) / (0.0282)2 = 112375 N/C, at a 45 degree angle pointing north east.
Now, take the sum of all three parts to find the net electric field.
A and C together point south west, with a magnitude of 31784.44 N/C.
112375 N/C - 31784.44 N/C = 80590.55 N/C, north east.
However, the answer given on the page is not what I got. What went wrong?