Calculate the emf of Battery w/ External & Internal Resistance

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SUMMARY

The discussion centers on calculating the electromotive force (emf) of a battery with given external and internal resistances. The external resistance is 2.50 ohms, and the current is 4.0 A, while the internal resistance is 0.50 ohms. The user correctly applies the equations V=IR and E=V+Ir to determine that the emf of the battery is 12 V. The calculations confirm that the logic used is sound, assuming the diagram aligns with the described parameters.

PREREQUISITES
  • Understanding of Ohm's Law (V=IR)
  • Knowledge of electromotive force (emf) concepts
  • Familiarity with internal and external resistance in circuits
  • Ability to interpret circuit diagrams
NEXT STEPS
  • Study the impact of varying internal resistance on battery performance
  • Learn about series and parallel circuit configurations
  • Explore advanced battery modeling techniques
  • Investigate the effects of temperature on battery resistance
USEFUL FOR

Students in physics or electrical engineering, educators teaching circuit theory, and anyone involved in battery technology or electrical circuit analysis.

Jabababa
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Homework Statement


What is the emf of the battery shown?

there is an external resistance of 2.50 ohm and 4.0 A...The battery has an internal resistance of 0.50ohm

Homework Equations



V=Ir
V= E +/- IR


The Attempt at a Solution



Since the current is going away the battery then i use the equation V= E - Ir
To find the V of the whole battery V= IR, V=(4)(2.5) = 10V
E= V + Ir
E= 10 + (4)(0.5) = 12 V

please check see if its right. If I am not clear i can upload a picture.
 
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Jabababa said:

Homework Statement


What is the emf of the battery shown?

there is an external resistance of 2.50 ohm and 4.0 A...The battery has an internal resistance of 0.50ohm

Homework Equations



V=Ir
V= E +/- IR


The Attempt at a Solution



Since the current is going away the battery then i use the equation V= E - Ir
To find the V of the whole battery V= IR, V=(4)(2.5) = 10V
E= V + Ir
E= 10 + (4)(0.5) = 12 V

please check see if its right. If I am not clear i can upload a picture.

Again your logic appears good - unless the diagram is quite unusual.
 

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