Calculate the energy lost to friction

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SUMMARY

The discussion focuses on calculating the energy lost to friction in a physics problem involving work done by friction. The user initially misinterprets the energy dissipated as the work done by friction, using the formula W = μmgcos(θ)d, where θ is the angle of inclination. After further analysis, the user correctly identifies the relationship between distance and height, concluding that the work of friction is -9.8257 Joules. The final formula used is W = 0.2 * mgcos(15°) * (h/sin(15°)).

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1. Homework Statement

http://i43.tinypic.com/i1bq1i.jpg
I need help with number 9

2. Homework Equations

Wnet=change in KE
Wnc=Change in Energy


The Attempt at a Solution


so I'm assuming the energy dissipated means the work done by friction?
so work of friction is umgcos(15)*d
d=cos(15)h
I got that work of friction is -9.8257
Help?
 
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nvm I figured it out.
.2*mgcos15*d
and the d=h/sin15
:approve:
 

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