The diffusion of Ni in FCC Fe. There is 0.3 atoms % of Ni in a solid solution in FCC Fe @ point x. Point y is 1 mm away and has 0.2 atoms % of Ni within the solid solution. Temperature = 1000° C, D = 2ε-16M2/s Calculate the flux (J) between points x & y. Radius of Fe atom = 0.13 nm @ 1000°C; a = 0.37nm. ATTEMPT AT A SOLUTION Ni is FCC 4 atoms in unit cell of FCC. a= 4T/(√3) # Atoms = 8*1028 J = -D(dc/dx) Δc = 1.6e26-2.4e26 Δx = 1mm = 1*10^-6 nm J = -1.6e25 is this right?